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Forum Discussion

Oscar's avatar
Oscar
Contributor
2 years ago
Solved

HttpClient Sample Code

I am trying to revamp the data integration between OneStream and Oracle Financial Cloud. The implementation partner used HttpWebRequest throughout the integration business rules but under platform 8....
XFBR
  • RobbSalzmann's avatar
    RobbSalzmann
    2 years ago

    I do something like this:

    string url = "http://www.example.com";

using (HttpClient client = new HttpClient())
{
    HttpResponseMessage response = await client.GetAsync(url);
    response.EnsureSuccessStatusCode();
    
    string content = await response.Content.ReadAsStringAsync();
    BRApi.ErrorLog.LogMessage(content);
}

    VB:

    Dim url As String = "http://www.example.com"

Using client As New HttpClient()
    Dim response As HttpResponseMessage = Await client.GetAsync(url)
    response.EnsureSuccessStatusCode()

    Dim content As String = Await response.Content.ReadAsStringAsync()
    BRApi.ErrorLog.LogMessage(content)
End Using

     

RobbSalzmann's avatar
RobbSalzmann
Valued Contributor II
2 years ago

I do something like this:

string url = "http://www.example.com";

using (HttpClient client = new HttpClient())
{
    HttpResponseMessage response = await client.GetAsync(url);
    response.EnsureSuccessStatusCode();
    
    string content = await response.Content.ReadAsStringAsync();
    BRApi.ErrorLog.LogMessage(content);
}

VB:

Dim url As String = "http://www.example.com"

Using client As New HttpClient()
    Dim response As HttpResponseMessage = Await client.GetAsync(url)
    response.EnsureSuccessStatusCode()

    Dim content As String = Await response.Content.ReadAsStringAsync()
    BRApi.ErrorLog.LogMessage(content)
End Using